y^2-4y-12x+16=0

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Solution for y^2-4y-12x+16=0 equation:


Simplifying
y2 + -4y + -12x + 16 = 0

Reorder the terms:
16 + -12x + -4y + y2 = 0

Solving
16 + -12x + -4y + y2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-16' to each side of the equation.
16 + -12x + -4y + -16 + y2 = 0 + -16

Reorder the terms:
16 + -16 + -12x + -4y + y2 = 0 + -16

Combine like terms: 16 + -16 = 0
0 + -12x + -4y + y2 = 0 + -16
-12x + -4y + y2 = 0 + -16

Combine like terms: 0 + -16 = -16
-12x + -4y + y2 = -16

Add '4y' to each side of the equation.
-12x + -4y + 4y + y2 = -16 + 4y

Combine like terms: -4y + 4y = 0
-12x + 0 + y2 = -16 + 4y
-12x + y2 = -16 + 4y

Add '-1y2' to each side of the equation.
-12x + y2 + -1y2 = -16 + 4y + -1y2

Combine like terms: y2 + -1y2 = 0
-12x + 0 = -16 + 4y + -1y2
-12x = -16 + 4y + -1y2

Divide each side by '-12'.
x = 1.333333333 + -0.3333333333y + 0.08333333333y2

Simplifying
x = 1.333333333 + -0.3333333333y + 0.08333333333y2

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